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Copy path10.maximum-subarray.js
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10.maximum-subarray.js
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// https://leetcode.com/problems/maximum-subarray/
// Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.
// A subarray is a contiguous part of an array.
// Example 1:
// Input: nums = [-2,1,-3,4,-1,2,1,-5,4]
// Output: 6
// Explanation: [4,-1,2,1] has the largest sum = 6.
// Example 2:
// Input: nums = [1]
// Output: 1
// Example 3:
// Input: nums = [5,4,-1,7,8]
// Output: 23
// Constraints:
// 1 <= nums.length <= 105
// -104 <= nums[i] <= 104
// Follow up: If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
/**
* @param {number[]} nums
* @return {number}
*/
var maxSubArray = function (nums) {
let currSum = -Infinity;
let maxSum = -Infinity;
for (let i = 0; i < nums.length; i++) {
currSum = Math.max(0, currSum);
currSum += nums[i];
maxSum = Math.max(maxSum, currSum);
}
return maxSum;
};