waitForTask: switch from polling every 5s to an incremental 2s, 3s, 4.5s, 6.75s, ~10s... progression #3738
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Optimizes for tasks finishing early by trying more often in the beginning,
but also ends up waiting longer for long-running tasks
this takes the default waitForTask max wait from$5 * 10 = 50s$ ,$\displaystyle\sum_{n=1}^{10} 2 * 1.5^n \approx 226s$ .
to
Related to AAH-2347 - we just need to wait a bit longer for long-running tasks.